Integrand size = 15, antiderivative size = 157 \[ \int \frac {x^3}{\left (a+b \sqrt {x}\right )^8} \, dx=\frac {2 a^7}{7 b^8 \left (a+b \sqrt {x}\right )^7}-\frac {7 a^6}{3 b^8 \left (a+b \sqrt {x}\right )^6}+\frac {42 a^5}{5 b^8 \left (a+b \sqrt {x}\right )^5}-\frac {35 a^4}{2 b^8 \left (a+b \sqrt {x}\right )^4}+\frac {70 a^3}{3 b^8 \left (a+b \sqrt {x}\right )^3}-\frac {21 a^2}{b^8 \left (a+b \sqrt {x}\right )^2}+\frac {14 a}{b^8 \left (a+b \sqrt {x}\right )}+\frac {2 \log \left (a+b \sqrt {x}\right )}{b^8} \]
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Time = 0.08 (sec) , antiderivative size = 157, normalized size of antiderivative = 1.00, number of steps used = 3, number of rules used = 2, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.133, Rules used = {272, 45} \[ \int \frac {x^3}{\left (a+b \sqrt {x}\right )^8} \, dx=\frac {2 a^7}{7 b^8 \left (a+b \sqrt {x}\right )^7}-\frac {7 a^6}{3 b^8 \left (a+b \sqrt {x}\right )^6}+\frac {42 a^5}{5 b^8 \left (a+b \sqrt {x}\right )^5}-\frac {35 a^4}{2 b^8 \left (a+b \sqrt {x}\right )^4}+\frac {70 a^3}{3 b^8 \left (a+b \sqrt {x}\right )^3}-\frac {21 a^2}{b^8 \left (a+b \sqrt {x}\right )^2}+\frac {14 a}{b^8 \left (a+b \sqrt {x}\right )}+\frac {2 \log \left (a+b \sqrt {x}\right )}{b^8} \]
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Rule 45
Rule 272
Rubi steps \begin{align*} \text {integral}& = 2 \text {Subst}\left (\int \frac {x^7}{(a+b x)^8} \, dx,x,\sqrt {x}\right ) \\ & = 2 \text {Subst}\left (\int \left (-\frac {a^7}{b^7 (a+b x)^8}+\frac {7 a^6}{b^7 (a+b x)^7}-\frac {21 a^5}{b^7 (a+b x)^6}+\frac {35 a^4}{b^7 (a+b x)^5}-\frac {35 a^3}{b^7 (a+b x)^4}+\frac {21 a^2}{b^7 (a+b x)^3}-\frac {7 a}{b^7 (a+b x)^2}+\frac {1}{b^7 (a+b x)}\right ) \, dx,x,\sqrt {x}\right ) \\ & = \frac {2 a^7}{7 b^8 \left (a+b \sqrt {x}\right )^7}-\frac {7 a^6}{3 b^8 \left (a+b \sqrt {x}\right )^6}+\frac {42 a^5}{5 b^8 \left (a+b \sqrt {x}\right )^5}-\frac {35 a^4}{2 b^8 \left (a+b \sqrt {x}\right )^4}+\frac {70 a^3}{3 b^8 \left (a+b \sqrt {x}\right )^3}-\frac {21 a^2}{b^8 \left (a+b \sqrt {x}\right )^2}+\frac {14 a}{b^8 \left (a+b \sqrt {x}\right )}+\frac {2 \log \left (a+b \sqrt {x}\right )}{b^8} \\ \end{align*}
Time = 0.10 (sec) , antiderivative size = 104, normalized size of antiderivative = 0.66 \[ \int \frac {x^3}{\left (a+b \sqrt {x}\right )^8} \, dx=\frac {a \left (1089 a^6+7203 a^5 b \sqrt {x}+20139 a^4 b^2 x+30625 a^3 b^3 x^{3/2}+26950 a^2 b^4 x^2+13230 a b^5 x^{5/2}+2940 b^6 x^3\right )}{210 b^8 \left (a+b \sqrt {x}\right )^7}+\frac {2 \log \left (a+b \sqrt {x}\right )}{b^8} \]
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Time = 5.99 (sec) , antiderivative size = 132, normalized size of antiderivative = 0.84
method | result | size |
derivativedivides | \(\frac {2 \ln \left (a +b \sqrt {x}\right )}{b^{8}}+\frac {2 a^{7}}{7 b^{8} \left (a +b \sqrt {x}\right )^{7}}-\frac {7 a^{6}}{3 b^{8} \left (a +b \sqrt {x}\right )^{6}}+\frac {42 a^{5}}{5 b^{8} \left (a +b \sqrt {x}\right )^{5}}-\frac {35 a^{4}}{2 b^{8} \left (a +b \sqrt {x}\right )^{4}}+\frac {70 a^{3}}{3 b^{8} \left (a +b \sqrt {x}\right )^{3}}-\frac {21 a^{2}}{b^{8} \left (a +b \sqrt {x}\right )^{2}}+\frac {14 a}{b^{8} \left (a +b \sqrt {x}\right )}\) | \(132\) |
default | \(\frac {2 \ln \left (a +b \sqrt {x}\right )}{b^{8}}+\frac {2 a^{7}}{7 b^{8} \left (a +b \sqrt {x}\right )^{7}}-\frac {7 a^{6}}{3 b^{8} \left (a +b \sqrt {x}\right )^{6}}+\frac {42 a^{5}}{5 b^{8} \left (a +b \sqrt {x}\right )^{5}}-\frac {35 a^{4}}{2 b^{8} \left (a +b \sqrt {x}\right )^{4}}+\frac {70 a^{3}}{3 b^{8} \left (a +b \sqrt {x}\right )^{3}}-\frac {21 a^{2}}{b^{8} \left (a +b \sqrt {x}\right )^{2}}+\frac {14 a}{b^{8} \left (a +b \sqrt {x}\right )}\) | \(132\) |
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Leaf count of result is larger than twice the leaf count of optimal. 315 vs. \(2 (131) = 262\).
Time = 0.30 (sec) , antiderivative size = 315, normalized size of antiderivative = 2.01 \[ \int \frac {x^3}{\left (a+b \sqrt {x}\right )^8} \, dx=-\frac {7350 \, a^{2} b^{12} x^{6} - 16905 \, a^{4} b^{10} x^{5} + 32585 \, a^{6} b^{8} x^{4} - 34370 \, a^{8} b^{6} x^{3} + 21504 \, a^{10} b^{4} x^{2} - 7413 \, a^{12} b^{2} x + 1089 \, a^{14} - 420 \, {\left (b^{14} x^{7} - 7 \, a^{2} b^{12} x^{6} + 21 \, a^{4} b^{10} x^{5} - 35 \, a^{6} b^{8} x^{4} + 35 \, a^{8} b^{6} x^{3} - 21 \, a^{10} b^{4} x^{2} + 7 \, a^{12} b^{2} x - a^{14}\right )} \log \left (b \sqrt {x} + a\right ) - 4 \, {\left (735 \, a b^{13} x^{6} - 980 \, a^{3} b^{11} x^{5} + 2891 \, a^{5} b^{9} x^{4} - 3072 \, a^{7} b^{7} x^{3} + 1981 \, a^{9} b^{5} x^{2} - 700 \, a^{11} b^{3} x + 105 \, a^{13} b\right )} \sqrt {x}}{210 \, {\left (b^{22} x^{7} - 7 \, a^{2} b^{20} x^{6} + 21 \, a^{4} b^{18} x^{5} - 35 \, a^{6} b^{16} x^{4} + 35 \, a^{8} b^{14} x^{3} - 21 \, a^{10} b^{12} x^{2} + 7 \, a^{12} b^{10} x - a^{14} b^{8}\right )}} \]
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Leaf count of result is larger than twice the leaf count of optimal. 1629 vs. \(2 (150) = 300\).
Time = 1.61 (sec) , antiderivative size = 1629, normalized size of antiderivative = 10.38 \[ \int \frac {x^3}{\left (a+b \sqrt {x}\right )^8} \, dx=\text {Too large to display} \]
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Time = 0.19 (sec) , antiderivative size = 131, normalized size of antiderivative = 0.83 \[ \int \frac {x^3}{\left (a+b \sqrt {x}\right )^8} \, dx=\frac {2 \, \log \left (b \sqrt {x} + a\right )}{b^{8}} + \frac {14 \, a}{{\left (b \sqrt {x} + a\right )} b^{8}} - \frac {21 \, a^{2}}{{\left (b \sqrt {x} + a\right )}^{2} b^{8}} + \frac {70 \, a^{3}}{3 \, {\left (b \sqrt {x} + a\right )}^{3} b^{8}} - \frac {35 \, a^{4}}{2 \, {\left (b \sqrt {x} + a\right )}^{4} b^{8}} + \frac {42 \, a^{5}}{5 \, {\left (b \sqrt {x} + a\right )}^{5} b^{8}} - \frac {7 \, a^{6}}{3 \, {\left (b \sqrt {x} + a\right )}^{6} b^{8}} + \frac {2 \, a^{7}}{7 \, {\left (b \sqrt {x} + a\right )}^{7} b^{8}} \]
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Time = 0.36 (sec) , antiderivative size = 95, normalized size of antiderivative = 0.61 \[ \int \frac {x^3}{\left (a+b \sqrt {x}\right )^8} \, dx=\frac {2 \, \log \left ({\left | b \sqrt {x} + a \right |}\right )}{b^{8}} + \frac {2940 \, a b^{5} x^{3} + 13230 \, a^{2} b^{4} x^{\frac {5}{2}} + 26950 \, a^{3} b^{3} x^{2} + 30625 \, a^{4} b^{2} x^{\frac {3}{2}} + 20139 \, a^{5} b x + 7203 \, a^{6} \sqrt {x} + \frac {1089 \, a^{7}}{b}}{210 \, {\left (b \sqrt {x} + a\right )}^{7} b^{7}} \]
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Time = 5.98 (sec) , antiderivative size = 159, normalized size of antiderivative = 1.01 \[ \int \frac {x^3}{\left (a+b \sqrt {x}\right )^8} \, dx=\frac {\frac {363\,a^7}{70\,b^8}+\frac {14\,a\,x^3}{b^2}+\frac {959\,a^5\,x}{10\,b^6}+\frac {385\,a^3\,x^2}{3\,b^4}+\frac {63\,a^2\,x^{5/2}}{b^3}+\frac {875\,a^4\,x^{3/2}}{6\,b^5}+\frac {343\,a^6\,\sqrt {x}}{10\,b^7}}{a^7+b^7\,x^{7/2}+21\,a^5\,b^2\,x+7\,a\,b^6\,x^3+7\,a^6\,b\,\sqrt {x}+35\,a^3\,b^4\,x^2+35\,a^4\,b^3\,x^{3/2}+21\,a^2\,b^5\,x^{5/2}}+\frac {2\,\ln \left (a+b\,\sqrt {x}\right )}{b^8} \]
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